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What is the angular momentum of an elect...

What is the angular momentum of an electron in `3P` orbital.

A

`3(h)/(2pi)`

B

`(h)/(sqrt(2)pi)`

C

`(1)/(2) (h)/(2pi)`

D

`(sqrt(2)h)/(pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
Orbital angular momentum is calculated by the following relation:
`sqrt(l(l+1))(h)/(2pi)`
where `l` is the angular momentum quantum number. For any `p` orbital, `l` is always equal to `1`, thus, the orbital angular momentum of a `3p` electron is
`sqrt(l(l+1))(h)/(2pi) = sqrt(2)(h)/(2pi) = (h)/(sqrt(2)pi)`
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