The de Broglie wavelength associated with a ball of mass `1kg` having kinetic enegry `0.5J` is

Options

A. `6.626 xx 10^(-34)m`
B. `13.20xx10^(-34)m`
C. `10.38xx10^(-21)m`
D. `6.626xx10^(-34)m`

Answer

A

Explanation

To calculate the de Broglie wavelength, we use the relation
`lambda = (h)/(mv)`
To calculate the velocity of the moving ball, we take the help of its kinetic enegry:
`KE = (1)/(2)mv^(2)`
`v^(2) = (2KE)/(m) v = sqrt(2KE)/(m) = sqrt(((2)(0.5kg m^(2)s^(-2)))/((1kg)))`
`= 1ms^(-1)`
Therefore,
`lambda = ((6.626 xx10^(-34)kg m^(2)s^(-1)))/((1kg)(1ms^(-1))) = 6.626 xx 10^(-34)m`