The number of `d` electrons in `Ni` (at.no `= 28`) is equal to that of the

Options

A. `s` and `p` electrons in `F^(-)`
B. `p` electrons in `Ar`(at.no `= 18)`
C. `d` electrons in `Ni^(2+)`
D. total electrons in `N`

Answer

C

Explanation

`Ni (Z = 28)`is `[Ar]3d^(8)4s^(2)`. After the removal of `2` electrons, w eget `Ni^(2+)` with the configuration `[Ar]3d^(8)`. Both `Ni` and `Ni^(2+)` ions have the same number of `d` electrons (i.e, `8`).