The atomic number of an element is `35`. What is the total number of eletrons present in all the `p` orbitals of the ground state of that element?

Options

A. `6`
B. `11`
C. `17`
D. `23`

Answer

C

Explanation

Accoridng to the Aufbau apporach, the ground state dectron configuraiton is
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3s^(10)4s^(2)3p^(5)`
Thus, the number of electron present in all the `p` orbitals is
`6 +6 +5 = 17`.