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Which of the following cations posses ne...

Which of the following cations posses neither noble gas nor pseudo noble gas configurations?
(i) `Bi^(3+)` (ii) `Pb^(2+)`
(iii) `Sn^(2+)` (iv) `Tl^(+)`

A

(ii), (iii)

B

(i), (iv)

C

(i), (ii), (iii)

D

(i), (ii), (iii), (iv)

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given cations (`Bi^(3+)`, `Pb^(2+)`, `Sn^(2+)`, `Tl^(+)`) possess neither noble gas nor pseudo noble gas configurations, we need to analyze the electronic configurations of each cation. ### Step 1: Identify the electronic configurations of the neutral atoms 1. **Bismuth (Bi)**: Atomic number = 83 - Electronic configuration: `[Xe] 4f^14 5d^10 6s^2 6p^3` 2. **Lead (Pb)**: Atomic number = 82 - Electronic configuration: `[Xe] 4f^14 5d^10 6s^2 6p^2` 3. **Tin (Sn)**: Atomic number = 50 - Electronic configuration: `Kr 4d^10 5s^2 5p^2` 4. **Thallium (Tl)**: Atomic number = 81 - Electronic configuration: `[Xe] 4f^14 5d^10 6s^2 6p^1` ### Step 2: Determine the electronic configurations of the cations 1. **Bismuth (Bi^(3+))**: - Remove 3 electrons from the outermost shell: - Configuration: `Bi^(3+)`: `[Xe] 4f^14 5d^10 6s^2 6p^0` (removing 3 electrons from 6s and 6p) 2. **Lead (Pb^(2+))**: - Remove 2 electrons from the outermost shell: - Configuration: `Pb^(2+)`: `[Xe] 4f^14 5d^10 6s^2 6p^0` (removing 2 electrons from 6p) 3. **Tin (Sn^(2+))**: - Remove 2 electrons from the outermost shell: - Configuration: `Sn^(2+)`: `[Kr] 4d^10 5s^2 5p^0` (removing 2 electrons from 5p) 4. **Thallium (Tl^(+))**: - Remove 1 electron from the outermost shell: - Configuration: `Tl^(+)`: `[Xe] 4f^14 5d^10 6s^2 6p^0` (removing 1 electron from 6p) ### Step 3: Analyze the configurations - **Noble gas configuration**: A cation has a noble gas configuration if its electronic configuration matches that of a noble gas (e.g., `Ne`, `Ar`, `Kr`, `Xe`). - **Pseudo noble gas configuration**: A cation has a pseudo noble gas configuration if it has a full outer shell (s and p) plus a filled d subshell. Now we check each cation: 1. **Bi^(3+)**: `[Xe] 4f^14 5d^10 6s^2 6p^0` - Matches noble gas configuration (Xe). 2. **Pb^(2+)**: `[Xe] 4f^14 5d^10 6s^2 6p^0` - Matches noble gas configuration (Xe). 3. **Sn^(2+)**: `[Kr] 4d^10 5s^2 5p^0` - Matches pseudo noble gas configuration (filled d subshell). 4. **Tl^(+)**: `[Xe] 4f^14 5d^10 6s^2 6p^0` - Matches noble gas configuration (Xe). ### Conclusion None of the cations `Bi^(3+)`, `Pb^(2+)`, `Sn^(2+)`, and `Tl^(+)` possess neither noble gas nor pseudo noble gas configurations. ### Final Answer All of the given cations possess either noble gas or pseudo noble gas configurations.

To determine which of the given cations (`Bi^(3+)`, `Pb^(2+)`, `Sn^(2+)`, `Tl^(+)`) possess neither noble gas nor pseudo noble gas configurations, we need to analyze the electronic configurations of each cation. ### Step 1: Identify the electronic configurations of the neutral atoms 1. **Bismuth (Bi)**: Atomic number = 83 - Electronic configuration: `[Xe] 4f^14 5d^10 6s^2 6p^3` 2. **Lead (Pb)**: Atomic number = 82 ...
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