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In forming ions, the atoms of transition...

In forming ions, the atoms of transition metals generally lose the ns electrons first, then they may lose one or more `(n-i)d` electrons. The `2+` ions are common for the transition elements and are obtained by the loss of the highest energy electrons from the atom except

A

`Ni`

B

`Fe`

C

`Cu`

D

`Co`

Text Solution

Verified by Experts

The correct Answer is:
C
`Cu(3d^(10)4s^1)rarrCu^(2+)(3d^9)+2e^(-)`
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R SHARMA-CHEMICAL BONDING-Follow-up Test 2
  1. Most of the monatomic ions of the representative elements are obtained...

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  2. Group 13 elements show less tendency to form ionic compounds than do g...

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  3. No compounds of representative elements are found with ions having cha...

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  4. There is a tendency for the elements of groups 13 to 15 of higher peri...

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  5. The elements fo groups 16 and 17 whose atoms have the largest negative...

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  6. Although the electron gain enthalpy of N(2s^2 2p63) is positive, the N...

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  7. Which of the following cations posses neither noble gas nor pseudo nob...

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  8. Many ions, particulary anions, are polyatomic. The atoms in these ions...

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  9. Cations are usually made from metals and anions are usually made from ...

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  10. Most transition metals from several cations having configurations.

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  11. In forming ions, the atoms of transition metals generally lose the ns ...

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  12. Many transition elements also form 3+ ions by losing one (n-1)d electr...

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  13. In case of transition metals, certain atoms can lose different numbers...

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  14. Many ionic compounds in transition metal ions are colored because of t...

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  15. Aqueous solutions of transition metal cations are also colored. Which ...

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  16. Which of the following catios forms colorless solution?

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  17. Which of the following transition metal catios have noble gas core? ...

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  18. For the formation of ionic bond between two atoms, the electronegativi...

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  19. Although for Mg, DeltaiH(378 kJ mol^(-1)) is greater than DeltaiH2 (14...

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  20. Although Na^(2+) has a higher charge and, therefore, NaCl2 should have...

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