The total number of electrons that take part in forming the bond in `N_2` is

Options

A. `10`
B. `6`
C. `4`
D. `2`

Explanation

To determine the total number of electrons that take part in forming the bond in the nitrogen molecule (N₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Valence Electrons in Nitrogen:**
- Each nitrogen atom has 5 valence electrons. This is because nitrogen has the electron configuration of 1s² 2s² 2p³.

2. **Calculate Total Valence Electrons in N₂:**
- Since there are two nitrogen atoms in the nitrogen molecule (N₂), the total number of valence electrons is:
\[ 5 \text{ (from one N)} + 5 \text{ (from the other N)} = 10 \text{ valence electrons.} \]

3. **Draw the Lewis Structure:**
- In the Lewis structure of N₂, each nitrogen atom will share three pairs of electrons (which corresponds to three covalent bonds). This means that each nitrogen atom contributes three electrons to the bonding.

4. **Count the Electrons Involved in Bonding:**
- Each of the three covalent bonds involves 2 electrons (one from each nitrogen atom). Therefore, the total number of electrons involved in bonding is:
\[ 3 \text{ (bonds)} \times 2 \text{ (electrons per bond)} = 6 \text{ electrons.} \]

5. **Consider Lone Pairs:**
- Each nitrogen atom has one lone pair of electrons (2 electrons) that do not participate in bonding. However, since the question specifically asks for the total number of electrons that take part in forming the bond, we only consider the bonding electrons.

6. **Final Answer:**
- Thus, the total number of electrons that take part in forming the bond in N₂ is **6**.

### Summary:
The total number of electrons that take part in forming the bond in \(N_2\) is **6**.