A sample of ozone gas occupies 117 mL at `100^(@) C`. At what temperature in degrees Celsius would it occupy `234 mL` if the pressure did not change?
Strategy : We know the volume of the gas at one temperature and we wish to know its temperature corresponding to a seconf volume(constant pressure). This implies the use of Charles'law, we must remember to carry out calculations with all temperatures expressed on the Kelvin scale , converting to or from Celsius as required.

Explanation

`{:("Initial conditions",,,"Fi nal conditions",),(V_(1) = 117 mL,,,V_(2) = 224,),(T_(1) = 100^(@) C + 273^(@),,,T_(2) = ?,):}`
`= 373 K`
According to Charles' law,
`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`
`:. T_(2) = (V_(2))/(V_(1)) xx T_(1)`
` = ((234 mL) (273 K))/((117 mL)) = 746 K`
`.^(@)C = 746 K - 273^(@) = 473^(@) C`