Calculate the temperature of `4.0 mol` of a gas occupying `5 dm^(3)` at 3.32 bar.
Strategy : List the variables with the proper units. Then solve the ideal gas equation for `T` by substituting the values.

Explanation

`T = ?" "n = 4.0 "mol"`
`V = 5 dm^(3)" "p = 3.32` bar
Solving `pV = nRT` for `T` and substituting the values gives
`T = (pV)/(nR) = ((3.32 ba r) (5 dm^(3)))/((4.0 "mol") (0.083 ba r L K^(-1) "mol"^(-1)))`
`= 50 K`