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The ratio between the root mean square s...

The ratio between the root mean square speed of `H_(2)` at `50 K` and that of `O_(2)` at `800 K` is

A

`2`

B

`4`

C

`1`

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
C
According to the kinetic molecular theory of gases , we have
`u_(rms) = sqrt((3 RT)/(M))`
`:. (u_(rms))_(H_(2))/((u_(rms))_(O_(2))) = sqrt((T_(H_(2)))/(M_(H_(2))) xx (M_(O_(2)))/(T_(O_(2))))`
`= sqrt((50 K)/(2 g mol^(-1)) xx (32 g mol^(-1))/(800 K))`
` = sqrt((1600)/(1600))`
`= 1`
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Knowledge Check

  • The ratio between the root mean square velocity of H_(2) at 50K and that of O_(2) at 800 K is "_______________" .

    A
    4
    B
    2
    C
    1
    D
    `(1)/(4)`

  • The ratio between the rms velocity of H_(2) at 50K and that of O_(2) at 800K is:

    A
    4
    B
    2
    C
    1
    D
    `(1)/(4)`

  • Root mean square velocity of O_2 at STP is (in cm/s)

    A
    `4.61 xx 10^(4)`
    B
    `2.6 xx 10^(4)`
    C
    `46.1 xx 10^(4)`
    D
    `26.0 xx 10^(4)`

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