If the `v_(rms)` is `30R^(1//2)` at `27^(@)C` then calculate the molar mass of gas in kilogram.

Options

A. `1`
B. `2`
C. `4`
D. `0.001`

Answer

A

Explanation

According to the Maxwell -Boltzmann distribution of speeds , we have
`u_(rms) = sqrt((3 RT)/(M))`
` :. (30 R^(1//2))^(2) = (3 RT)/(H)`
`900 R = (3 R ( 27 + 273))/(M)`
`M = (900 R)/(900 R) = 1 g mol^(-1)`
` = 10^(-3) kg mol^(-1)`