The volume occupied by 4.4 g of `CO_(2)` at STP is

Options

A. `2.4 L`
B. `2.24 L`
C. `44 L`
D. `22.4 L`

Answer

B

Explanation

`n_(CO_(2)) = ("Mass"_(CO_(2)))/("Molar mass"_(CO_(2))) = (4.4 g)/(44 g "mol"^(-1)) = 0.1 "mol"`
Under `STP` conditions ,
`n_(CO_(2)) = (V_(CO_(2)) "inliters at STP")/(22.4 L" mol"^(-1))`
`0.1 "mol" = (V_(CO_(2)) "inliters at STP")/(22.4 L mol^(-1))`
or `V_(CO_(2)) = (0.1 "mol") (22.4 L "mol"^(-1))`
`= 2.24 L`