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The enthalpy of certain reaction at 273 ...

The enthalpy of certain reaction at `273 K` is `-20.75 kJ`. The enthalpy of the same reaction at `373 K` provided heat capacities fo reactants and products are the same) will be

A

`- 2075 kJ`

B

zero

C

`20.75 xx (373)/(273) kJ`

D

`- 20.75 kJ`

Text Solution

Verified by Experts

The correct Answer is:
D

According to Kirchoff's equation,
`Delta_ H_(2) Delta H_(1) = Delta C_(P) (T_(2) - T_(1))`
Since `(C_(P))_("Products") = (C_(P))_("reactants")`, we have `Delta C_(P) = 0`, Thus,
`Delta H_(2) - Delta H_(1) = 0` ltbr gt or `Delta H_(2) = Delta H_(1)`
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