The work done during the expanision of a gas from a volume of `4 dm^(3)` to `6 dm^(3)` against a constant external pressure of 3 atm is (1 L atm = 101.32 J)

Options

A. `- 6 J`
B. `- 608 J`
C. `+ 304 J`
D. `- 304 J`

Answer

B

Explanation

Work done by the system during an irreversible expansion againt a constant atmospheric pressure is given by
`W = - P_(ext) Deltav = - P_(ext) (V_(f) - V_(i))`
`= - 3 atm (6 L - 4 L)`
`= - 6 L atm`
` = - L atm ((101.32 J)/(1 L atm))`
`= - 607.92 kJ`