The densities of graphite and diamond at `298K` are `2.25` and `3.31gcm^(-3)` , respectively. If the standard free energy difference `(DeltaG^(0))` is equal to `1895Jmol^(-1)` , the pressure at which graphite will be transformed into diamond at `298K` is

Options

A. `9.92 xx 10^(8) Pa`
B. `9.92 xx 10^(7) Pa`
C. `9.92 xx 10^(6) Pa`
D. `9.92 xx 10^(5) Pa`

Answer

D

Explanation

Since we are dealing with standard conditions, the pressure must be 1 bar `(10(5) Pa)` and the temperature must be specified, usually `298 K`.