2 mol of an ideal gas at `27^(@)C` temperature is expanded reversibly from `2L` to `20L`. Findk entropy change `(R = 2 cal mol^(-1) K^(-1))`

Options

A. 92.1
B. 0
C. 4
D. 9.2

Answer

D

Explanation

`Delta S` for the isothermal reversible expansion of an ideal gas is given as
`Delta S = 2.303 nR log ((V_(2))/(V_(1)))`
`= (2.303) (2) (2) "log" (20)/(2)`
`= (9.212) log 10`
`= 9.2 cal K^(-1) mol^(-1) (log 10 = 1)`