Compound ` CrO_5` has structure as shown
ltbtgt The oxidation number fo Cr in the above compound is .

Options

A. `10`
B. `5`
C. `4`
D. `6`

Answer

D

Explanation

In the given compound, there are four oxygen atoms in the peroxidge while the fifth oxygen is in the oxide state. If we assume that the oxidation state fo Cr in ` CrO_5` is `x` then
` x+ (-2) + 4 (-4) =0` ltbgt ` x-6 =0`
` x-=+6`
Alternatively, we can work out the oxidation number by breaking the bonds heterolytically. Since Cr is forming six bonds whith O atoms, it loses `6` electrons when bonding electrons are given to oxgne. Thus, its oxidation number is `+6`.