Oxidation numbers fo iodine in ` IO_3^(-), IO_4^(-), Kl`, and `I_3` , respectively, are .

Options

A. ` +5, +7, -1, 0`
B. ` -1, -5, -1, 0`
C. ` -2, -5 , -1, 0`
D. ` +3, +5, +7, 0`

Answer

A

Explanation

The algebraic sum of the oxidation number of all the atoms in a compound must be zero and in a polyatomic ion must equal the charge on the ion. Let the oxidation number or iodine be `x`. Then
`IO_3^(-) rArr x+ 3(-2) =- 1`
`x=+5`
` IO_4^(-) rArr x + 4 (-2) =- 1`
` x =+7`
`KI rArr ( +1) + (x) =0`
` x=- 1`
` I_2 rArr 2 x =0`
` x = 0`.