The oxidation number of `Cl` in `CaOCl_(2)` is

Options

A. ` +1`
B. `-1`
C. `+1-1`
D. `0`

Answer

C

Explanation

`CaCl_2` is an ionic compound having the composition ` Ca^(2+) (OCI^(-))CI^(-)`. Therefore, the oxidation number of ` CI` in ` OCI^(-)` is ` [-2 +x =- 1] +1` and in `CI^(-)` is ` -1`.