When boric acid is heated at `160^(@)C`, the product is

Options

A. boric anhydride
B. metaboric acid
C. tetraboric acid
D. pyroboric acid

Explanation

To determine the product when boric acid (H₃BO₃) is heated at 160°C, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Boric Acid**:
- Boric acid has the chemical formula H₃BO₃. It consists of boron (B), oxygen (O), and hydrogen (H) atoms.

2. **Heating Boric Acid**:
- When boric acid is heated, it undergoes dehydration, meaning it loses water molecules.

3. **Temperature Consideration**:
- At 160°C, boric acid will lose water molecules. Specifically, it will lose one water molecule (H₂O) during this process.

4. **Formation of Tetra Boric Acid**:
- The reaction can be represented as:
\[ 4 \, H_3BO_3 \rightarrow H_2B_4O_7 + 5 \, H_2O \]
- Here, H₂B₄O₇ is known as Tetra Boric Acid.

5. **Final Product**:
- Therefore, when boric acid is heated at 160°C, the product formed is Tetra Boric Acid (H₂B₄O₇).

### Summary of the Reaction:
- Heating H₃BO₃ at 160°C results in the formation of Tetra Boric Acid (H₂B₄O₇) and the release of water.