An alkane with the molecular formula `C_(6)H_(14)` forms only three monochloro derivatives on chlorination. The name of the alkane is

Options

A. neohexane
B. `3`-methylpentane
C. `2,3`-dimethylbutane
D. isohexane

Answer

A

Explanation

It has `3` different types of replaceable `H` atoms.

Compound (2): `overset(1_(b)^(@))(CH_(3))overset(2^(@))CH_(2)underset(1_(a)^(@)CH_(3))underset(|)overset(3^(@))(CH)overset(2^(@))CH_(2)-overset(1_(b)^(@))CH_(3)rarr4 "Products"`
Compound (3): `overset(1^(@))CH_(3)underset(1^(@))underset(CH_(3))underset(|)overset(2^(@))(CH)underset(1^(@))underset(CH_(3))underset(|)overset(2^(@))(CH)overset(1_(b)^(@))(CH_(3))rarr2 "Products"`
Compound (4): `overset(1_(b)^(@))(CH_(3)underset(1_(b)^(@)CH_(3))underset(|)overset(3^(@))(CH))overset(2_(b)^(@))(CH_(2))overset(2_(a)^(@))(CH_(2))overset(1_(a)^(@))(CH_(3))rarr5 "Products"`