The relative reactivity of `1^(@) : 2^(@) : 3^(@) H's` to brominate is `1:82:1600`, respectively. In the reaction
`CH_(3)-underset("Excess")overset(CH_(3))overset(|)(CH)CH_(3)+Br_(2)overset(hv)rarrCH_(3)underset((A))underset(Br)underset(|)overset(CH_(3))overset(|)(C) CH_(3)+underset((B))overset(CH_(3))overset(|)(CH_(3))CHCH_(3)Br`
the percentage yield of the products `(A)` and `(B)` are expected to be

Options

A. `72,28`
B. `80,20`
C. `99.4,0.6`
D. `4.65,35`

Answer

C

Explanation

`(("Relative amount"),(of "product"))=(("Relative"),("reactivity"))xx(("Number of "),("equivalent H's"))`
Thus,
Relative amount of `A= (1600)(1)= 1600`
Relative amount of `B= (1) (9)= 9`
`"Percentage yield"=("Relative amount of product")/("Sum of the relative amounts")xx100%`
`"Percentage of A"=(1600)/(1609)xx100%= 99.4%`
`"Percentage of B"=(9)/(1609)xx100%= 0.6%`