`CH_(3)CH=CH_(2)+BrC Cl_(3)overset("Peroxide")rarr`
The major product of the reaction is

Options

A. `CH_(3)CHClCH_(2)CBrCl_(2)`
B. `CH_(3)CHBrCH_(2)C Cl_(3)`
C. `ClCH_(2)CHBrCG_(2)CHCl_(2)`
D. `BrCH_(2)CHClCH_(2)CHCl_(2)`

Explanation

To solve the given problem, we need to analyze the reaction between propene (CH₃CH=CH₂) and bromotrichloromethane (BrCCl₃) in the presence of peroxide. This reaction involves free radical mechanisms, which are crucial for determining the major product. Let's break down the steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The alkene is propene (CH₃CH=CH₂).
- The reagent is bromotrichloromethane (BrCCl₃).

2. **Understand the Role of Peroxide**:
- The presence of peroxide initiates a free radical mechanism. Peroxides decompose to form free radicals, which will facilitate the reaction.

3. **Formation of Free Radicals**:
- When peroxide (RO-OR) decomposes, it generates free radicals (RO•). These free radicals are highly reactive and will attack the alkene.

4. **Attack of Free Radical on BrCCl₃**:
- The free radical generated from the peroxide will attack BrCCl₃. The bond between Br and C will break because the C-Cl bond is stronger than the C-Br bond. This results in the formation of a bromine radical (Br•) and a trichloromethyl radical (CCl₃•).

5. **Formation of New Free Radical**:
- The bromine radical (Br•) will then attack the propene (CH₃CH=CH₂). The double bond in propene will break, and the Br• will add to one of the carbons, forming a new radical on the adjacent carbon.

6. **Stability of the Radical**:
- The radical formed will be more stable if it is on a secondary carbon rather than a primary carbon. Therefore, the Br will add to the terminal carbon (CH₂), and the radical will be on the secondary carbon (CH).

7. **Final Product Formation**:
- The final product will be 1-bromo-2-chloropropane (CH₃CH(Br)CH₂CCl₃) because the CCl₃ group will be attached to the more stable radical carbon.

8. **Conclusion**:
- The major product of the reaction is 1-bromo-2-chloropropane (CH₃CH(Br)CH₂CCl₃).

### Final Answer:
The major product of the reaction is **1-bromo-2-chloropropane (CH₃CH(Br)CH₂CCl₃)**.