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CH(2)=CH(2)overset(HOCl)rarrAoverset(dil...

`CH_(2)=CH_(2)overset(HOCl)rarrAoverset(dil.NaOH)rarrB`
The final product `B` formed in the above reaction is

A

`HOCH_(2)CH_(2)OH`

B

C

`ClCH_(2)CH_(2)Ona`

D

`ClCH_(2)CH_(2)OH`

Text Solution

Verified by Experts

The correct Answer is:
B
`CH_(2)=CH_(2)overset(HOCl)to underset(OH)underset(|)CH_(2)-underset(Cl)underset(|)CH_(2)`
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