In fcc unit cell the radius of each atom (sphere) is releated to the edge length ( or side) of the cube as
A
`r=(sqrt(3))/(2)a`
B
`r=(sqrt(3))/(4)a`
C
`r=sqrt(3)a`
D
`r=(4)/(sqrt(3))`
Text Solution
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The correct Answer is:
2
The length of the body diagonal is equal to `sqrt(3)a` .In bcc unit cell , all the three spheres(atoms) along the diagonal touch each other.therefore ` 4r=sqrt(3a)` `r=(sqrt(3))/(4)a`.
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