Anaysis shows that nickel oxide has the formula `NI_(0.90)O_(1.00)`. Fractional of nickel existing as `Ni^(2)` and `Ni^(3+)` ions respectively. Are

Options

A. `4%` and `96%`
B. `96%` and `4%`
C. `6%` and `94%`
D. `94%` and `6%`

Answer

2

Explanation

According to the formula `M_(0.98)O_(1.00)`, If we consider `100` oxygen atoms.then there should be `98Ni` atoms existing as `Ni^(2+)` and `Ni^(3+)` ions.
Charge carried by `100` oxide ions `(O^(2-))=(-2)(100)`
`=-200`
Let's assume that there are `Ni^(2+)` ions then number of `Ni^(3+)` ion should be `98-x`.
Total positive charge carried by `NI^(2+)` and `NI^(3+)` ions will be
`(+2)(x)+(+3)(98-x)`
`=2x+294-3x`
`=294-x`
Simple nickle oxide as a whole is electrically neutral total charge on cations should be equal to total charge on anions:
`294-x=200`
or `x=94`
Therefore `%` of `Ni` as `NI^(2+)=(94)/(98)xx100%=95%`
and `%` of `Ni` and `Ni^(3+)=100%-96%`
`=4%`