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The ionic radii of A^(+) and B^(-) ions ...

The ionic radii of `A^(+)` and `B^(-)` ions are `0.98xx10^(-10)m` and `1.81xx10^(-10)m`.The coordination number of each ion in `AB` is :

A

`2`

B

`6`

C

`4`

D

`8`

Text Solution

Verified by Experts

The correct Answer is:
2
Let calculate the radius ratio:
`(r_(+))/(r_(-))=(0.98xx10^(10)m)/(1.81xx10^(-10)m)=0.541`
Since it lies the range `0.414-.732` ,the coordination number of each ion is `6`.
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