Calculating cell constant: Conductivity of a decimolar solution of potassium chloride at `180^(@)C` is `1.12 Sm^(-1)`. The resistance of a conductivity cell containing the solution at `180^(@)C` was found to be `55 ohm`. What is the cell constant.
Strategy: Use Equation (3.18) and solve for cell constant.

Explanation

Conductance `(G) = 1//R = (1)/(55) S`
Conductance `(K) = 1.12 Sm^(-1)`
Substituting these results into Equation (3.18) solving for cell constant, we have
cell constant `(l//A) = (K)/(G)`
`= (1.22 Sm^(-1))/(1//55)S`
`61.6 m^(-1)`
`= 0.616 cm^(-1)`