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A solution containing one mole per litre...

A solution containing one mole per litre of each `Cu(NO_(3))_(2), AgNO_(3), Hg_(2)(NO_(3))_(2)` is being electrolysed by using inert electrodes. The values of standard electrode potentials in volts (reduction potentials) are
`Ag^(+)//Ag = +0.80 V, HG_(2)^(2+)//Hg = +0.79 V`
`Cu^(+)//Cu = +0.34 V, Mg^(2+)//Mg = -2.37 V`
With increasing valtage, the sequence of deposition of metals on the cathode will be

A

`Cu, Hg, Ag`

B

`Ag, Hg, Cu, Mg`

C

`Ag, Hg, Cu`

D

`Mg, Cu, Hg, Ag`

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The correct Answer is:
To determine the sequence of deposition of metals on the cathode during the electrolysis of a solution containing `Cu(NO3)2`, `AgNO3`, and `Hg2(NO3)2`, we need to analyze the standard electrode potentials provided for each metal ion. The standard electrode potentials indicate how easily a metal ion can be reduced to its metallic form. The higher the potential, the more favorable the reduction reaction. ### Step-by-Step Solution: 1. **Identify the Standard Electrode Potentials:** - For `Ag^+ + e^- → Ag`, E° = +0.80 V - For `Hg2^2+ + 2e^- → 2Hg`, E° = +0.79 V - For `Cu^2+ + 2e^- → Cu`, E° = +0.34 V - For `Mg^2+ + 2e^- → Mg`, E° = -2.37 V 2. **Rank the Metals by Their Standard Electrode Potentials:** - The metals can be ranked from highest to lowest standard reduction potential: - Ag: +0.80 V - Hg: +0.79 V - Cu: +0.34 V - Mg: -2.37 V 3. **Consider the Feasibility of Deposition:** - The metals with higher standard reduction potentials will deposit first when the voltage is increased. - However, since the standard reduction potential of magnesium is negative (-2.37 V), it indicates that magnesium will not be deposited under normal electrolysis conditions. The reduction potential of water (which is higher than that of magnesium) will take precedence over magnesium. 4. **Determine the Sequence of Deposition:** - Based on the above analysis, the sequence of deposition of metals on the cathode, with increasing voltage, will be: - First: Ag (Silver) - Second: Hg (Mercury) - Third: Cu (Copper) - Therefore, the final sequence is Ag, Hg, Cu. 5. **Conclusion:** - The sequence of deposition of metals on the cathode is: **Ag, Hg, Cu**.

To determine the sequence of deposition of metals on the cathode during the electrolysis of a solution containing `Cu(NO3)2`, `AgNO3`, and `Hg2(NO3)2`, we need to analyze the standard electrode potentials provided for each metal ion. The standard electrode potentials indicate how easily a metal ion can be reduced to its metallic form. The higher the potential, the more favorable the reduction reaction. ### Step-by-Step Solution: 1. **Identify the Standard Electrode Potentials:** - For `Ag^+ + e^- → Ag`, E° = +0.80 V - For `Hg2^2+ + 2e^- → 2Hg`, E° = +0.79 V - For `Cu^2+ + 2e^- → Cu`, E° = +0.34 V ...
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