The ground state electronic configuration of platinum is

Options

A. `[Xe] 4f^(14) 5d^(9) 6s^(1)`
B. `[Kr] 4d^(10) 5s^(0)`
C. `[Xe] 4f^(14) 5d^(8) 6s^(2)`
D. `[Kr] 4d^(4) 5s^(1)`

Answer

A

Explanation

The expected configuratiuon of Pt is `[Xe]4f^(14 5d^(8) 6s^(2)` but its actual confinguration is `[Xe]4f^(14) 5d^(9) 6s^(1)` . Second configuration corresponds to Pd, third one corresponds to Ag and fourth one corresponds to Nb.