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The correct of decreasing second ionisat...

The correct of decreasing second ionisation enthalpy of `Ti(22),V(23),Cr(24)` and `Mn(25)` is

A

`Ti gt V gt Cr gt Mn`

B

`Cr gt Mn gt V gt Ti`

C

`V gt Mn gt Cr gt Ti`

D

`Mn gt Cr gt TI gt V`

Text Solution

Verified by Experts

The correct Answer is:
B
In general, ionization enthalpy increases as we move across the period on account of increases of effective nuclear charge. But Cr has unsually high `Delta_(i)H_(2)` on account of extra stability of `d^(5)` configuration of `Cr^(+)` ion. Thus, the correct order is
`Cr gt Mn gt V gt Ti`
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