Among the following series of transition metal ions the one where all meal ions have `3d^2` electronic configuration is

Options

A. `Ti^(3+) , V^(2+) , Cr^(3+) , Mn^(4+)`
B. `Ti^(+)` , `V^(4+)` , `Cr^(6+)` , `Mn^(7+)`
C. `Ti^(+)` , `V^(4+)` , `Cr^(6+)` , `Mn^(7+)`
D. `Ti^(2+)` , `V^(3+)` , `Cr^(4+)` , `Mn^(5+)`

Answer

D

Explanation

`Ti (3d^(2) 4s^(2)) implies Ti^(+) (3d^(2) 4s^(1)) implies Ti^(2+) (3d^(2)) implies Ti^(3+) (3d^(1))`
`V (3d^(3) 4s^(2)) implies V^(2+) (3d^(2)) implies V^(4+) (3d^(1))`
`Cr (3d^(5) 4s^(1)) implies Cr^(3+) (3d^(3)) implies Cr^(4+) (3d^(2)) implies Cr^(6+) (3d^(0))`
`Mn (3d^(5) 4s^(2)) implies Mn^(4+) (3d^(3)) implies Mn^(5+) (3d^(2)) implies Mn^(7+) (3d^(0))`