The IUPAC name for `[CO)_(5)` Mn-Mn `(CO)_(5)]` is

Options

A. bis[pentacarbonylmanganate (VIII)]
B. decarbonyldimanganate (VIII)
C. bis(pentracarbonylmanganese (0)]
D. bis(pentacarbonyldimanganese)

Explanation

To derive the IUPAC name for the compound \([Mn_2(CO)_5]\), we can follow these steps:

### Step 1: Identify the Components
The compound consists of two manganese (Mn) atoms and five carbon monoxide (CO) ligands.

### Step 2: Determine the Oxidation State
In this complex, the carbon monoxide (CO) is a neutral ligand, and since there are no other anions present, the oxidation state of manganese can be determined to be zero. Therefore, we have Mn in the oxidation state of 0.

### Step 3: Naming the Ligands
The carbon monoxide ligands are named "carbonyl." Since there are five CO ligands, we use the prefix "penta-" to indicate the number of ligands. Thus, we have "penta-carbonyl."

### Step 4: Naming the Metal
The metal in this case is manganese (Mn). Since there are two manganese atoms, we use the prefix "bis-" to indicate the presence of two manganese atoms. Therefore, we write "bis-manganese."

### Step 5: Combining the Names
Now we combine the names of the ligands and the metal along with the oxidation state. The complete name will be:
- Ligands: "penta-carbonyl"
- Metal: "bis-manganese"
- Oxidation state: "zero"

Putting it all together, we get the IUPAC name:
**bis-penta-carbonyl-dimanganese(0)**

### Final Answer
The IUPAC name for \([Mn_2(CO)_5]\) is **bis-penta-carbonyl-dimanganese(0)**.

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