An excess of `AgNO_(3)` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromium(III) chloride The number of moles of `AgCI` precipitated would be .

Options

A. `0.002`
B. `0.003`
C. `0.01`
D. `0.001`

Answer

D

Explanation

`[Cr(H_(2)O)_(4)C1_(2)]C1 implies 1` mol AgC1
1 mol
no of mooles = (Molarity)(Vol. of soln. in litres)
`= (0.01 M) (0.1 L)`
`= 0.001`
Thus, `0.001` mol of complex will yield `0.001` mol of AgC1