Crystal field stabilization energy for high spin `d^4` octahedral complex is

Options

A. `-0.6 Delta_(0)`
B. `-1.8 Delta_(0)`
C. `-1.8 Delta_(0) + P`
D. `-1.2 Delta_(0)`

Answer

A

Explanation

Higher spin `d^(4)` octahedtral complex is formed in weak ligand field:

The total crystal field stabilization energy is given by `CFSE_(("octahedral")) = [-0.4n_((t_(2g))) + 0.6n_((e_(g)))] Delta_(0)`
where `n_((t_(2g)))` and `n_((e_(g)))` are the number of electrons occupying the `t_(2g)` and `e_(g)` orbitals respectively. Thus
`CFSE = [-0.4(3) + 0.6(1)]Delta_(0)`
`= [-1.2+ 0.6] Delta_(0)`
`= -0.6 Delta_(0)`