Coordination number of `Ni` in `[Ni(C_2O_4)_3]^(4-)` is:

Options

A. 3
B. 6
C. 4
D. 2

Answer

B

Explanation

Since oxalate ion, `C_(2)O_(4)^(2-)` , is a didentate ligand, there are 2 donor atoms per ligand. Thus, coordination number of `Ni^(2+)` in the given complex ion is six.