The interchange of two groups `(Br`and `CH_(3)` at the chiral centre of the projection formula `(A)` yields the fromula `(B)`,while the interchange of another set of two groups `(C_(2)H_(5)` and `CI)` of `(A)` yields the projection formula `(C )`.

Which of the following statemenets is not correct about the structures `(A),(B)` are `(C )`?

Options

A. `(A)`and`(B)`are enantiomers
B. `(A)`and`(C )` are enantiomers
C. `(B)`and`(C )` are identical
D. `(B)`and`(C )` are enantiomers

Answer

D

Explanation

An odd number `(1,3,5,….)` of switches changes the configuration to that of the enantiomer. Thus `(A)` and `(B)` are enantiomers. Similarly `(A)` and `(C )` are also enantiomers.
An even number `(2,4,6…)` of switches result in no change in the configuration. Thus `(B)` and `(C )` are not enantiomers bur ate identical compounds as we can convert `(B)` into `(C )` by two interchanges.