Find the value of `tan(sin^(-1)(3/5)+cot^(-1)(3/2))`

Explanation

To find the value of \( \tan(\sin^{-1}(3/5) + \cot^{-1}(3/2)) \), we will follow these steps:

### Step 1: Define the angles
Let:
- \( A = \sin^{-1}(3/5) \)
- \( B = \cot^{-1}(3/2) \)

### Step 2: Use the tangent addition formula
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