A force `F=2x+3x^2`N acts on a particle in the x-direction. Find the work done by this force during a displacement `x=1.0m ` to `x=2.0m`

Explanation

Here force is variable
`W=int_(x1)^(x2)Fdx=int_1^2(2x+3x^2)dx`
`=2.(x^2)/(2)+3(x^3)/(3)=|x^2+x^3|_1^2`
`={(2)^2+(2)^3}-{1^2+1^3}=12-2=10J`