A particle moves from position 3hati+2ha...

A particle moves from position `3hati+2hatj-6hatk` to `14hati+13hatj+9hatk` due to a force `vecF=(4hati+hatj+3hatk)`N. If the displacement is in centimeter then work done will be

`1J`

`2J`

`3J`

`2.5J`

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The correct Answer is:

`vecr_1=3hati+2hatj-6hatk`,`vecr_2=14hati+13hatj+9hatk`
`vecd=vecr_2-vecr_1=(11hati+11hatj+15hatk)cm`
`vecF=(4hati+hatj+3hatk)N`
`W=vecF.vecd=(44+11+45)xx10^(-2)=1J`

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