A particle of mass 2 kg is moving in a straight line such that its velocity is given by `v=3t^2(m)//(s)`, where t is in second. Find the work done by all forces in the first 2 s of its motion.

Explanation

`v=3t^2`
`t=0`,`v_1=0`,`K_1=0`
`t=2s`,`v_2=3(2)^2=12(m)/(s)`
`K_2=(1)/(2)mv_2^2=(1)/(2)xx2xx(12)^2=144J`