(a) What is the power of an engine which can lift 600 kg of coal per minut from a mine 20 m deep ?
(b) A 2kW motor pumps out water from a well `10m` deep. Calculated the quantity of water pumped out per second.

Explanation

`overlineP=(W)/(t)=(mgh)/(t)=(600xx10xx20)/(60)=2000W`
(b) `overlineP=(W)/(t)=(mgh)/(t)`
`2000=(m)/(t)xx10xx10`
`(m)/(t)=20`
Quantity of water pumped out per second `=20kg`