The displacement `x` of a particle of mass `m` kg moving in one dimension, under the action of a force, is related to the time t by the equation `t=4x+3` where `x` is in meters and `t` is in seconds. The work done by the force in the first six seconds in joules is

Options

A. 0
B. 3 m
C. 6 m
D. 9 m

Answer

A

Explanation

`t=4x+3impliesx=(1)/(4)(t-3)`
`v=(1)/(4)(1)=(1)/(4)(m)//(s)`
Since the velocity is constant.
`W=triangleK=0`