A block of mass `m` at rest is acted upon by a force `F` for a time t. The kinetic energy of block after time t is

Options

A. `(Ft^2)/(m)`
B. `(F^2t^2)/(2m)`
C. `(Ft^2)/(2m)`
D. `(F^2t^2)/(3m)`

Answer

B

Explanation

`a=(F)/(m)`
`s=(1)/(2)at^2=(Ft^2)/(2m)`
`W=triangleK`
`Fs=K-0impliesK=(F^2t^2)/(2m)`