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A mass of `0.5 kg` moving with a speed of `1.5 m//s` on a horizontal smooth surface, collides with a nearly weightless spring of force constant `k =50 N//m` The maximum compression of the spring would be.

A

`0.15m`

B

`0.12m`

C

`1.5m`

D

`0.5m`

Text Solution

Verified by Experts

The correct Answer is:
A


`(1)/(2)mv^2=(1)/(2)kx^2`, `x:` maximum compression of spring
`x=vsqrt((m)/(k))=(1.5)sqrt((0.5)/(50))=0.15m`
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