A car is moving along a stight horizonta...

A car is moving along a stight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyres and the road is mu, the shortest distance in which the car can be stopped is.

`(v_0^2)/(mug)`

`(v_0^2)/(4mug)`

`(v_0^2)/(2mug)`

`(2v_0^2)/(mug)`

Text Solution

Verified by Experts

The correct Answer is:

`(1)/(2)mv_0^2=fs=mugs`
`s=(v_0^2)/(2mug)`

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