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A particle is placed at the origin and a...

A particle is placed at the origin and a force F=Kx is acting on it (where k is a positive constant). If `U_((0))=0`, the graph of `U (x)` verses x will be (where U is the potential energy function.)

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Verified by Experts

The correct Answer is:
A
`F=kx`
`U=-int_(0)^(x)Fdx=-int_(0)^(x)kxdx=-(1)/(2)kx^2`
U v/s x graph will be a parabola, open downward
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