Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of erth =12800 km andit takes 24 hour for the earth to comlete one revolution about its axis.

Explanation

Angular speed of the earth
`omega=(2pi)/(T)=(2pi)/(24xx60xx60)rad//s`
radial acceleration
`a_(r)=a_(c)=omega^(2)R_(e)`
`=((2pi)/(24xx60xx60))^(2)xx(6400xx10^(3))=0.033m//s^(2)`