A train has to negotitate a curve of radius `2000m`. By how much should the outer rail be raised with respect to inner rail for a speed`72 km//h`. The distance between the rails is `1m`.

Explanation

we have `tan theta=(v^(2))/(Rg)`
`tan theta=(h)/(l)`
`(v^(2))/(Rg)=(h)/(l)impliesh=(v^(2)l)/(Rg)`
`v=72km//h=72xx(5)/(18)=20m//s`
`l-1m,R=2000m,g=10m//s^(2)`
`h=((20)^(2)xx1)/(2000xx10)=(1)/(50)m=(100)/(50)=2cm`