A particle moves in a circle of radius 5 cm with constant speed and time period `0.2pis`. The acceleration of the particle is

Options

A. `5m//s^(2)`
B. `15m//s^(2)`
C. `25m//s^(2)`
D. `36m//s^(2)`

Answer

A

Explanation

`T=(2pi)/(omega)impliesomega=(2pi)/(T)=(2pi)/(0.2pi)=10rad//s`
`a_(c)=omega^(2)r=(10)^(2)xx(5)/(100)=5 m//s^(2)`